(y-3)^2/3=(10y-54)^1/3

Solution for (y-3)^2/3=(10y-54)^1/3 equation:

y in (-oo:+oo)

((y-3)^2)/3 = ((10*y-54)^1)/3 // - ((10*y-54)^1)/3

((y-3)^2)/3-(((10*y-54)^1)/3) = 0

((y-3)^2)/3-((10*y-54)/3) = 0

((y-3)^2)/3+(-1*(10*y-54))/3 = 0

(y-3)^2-1*(10*y-54) = 0

y^2-16*y+63 = 0

y^2-16*y+63 = 0

y^2-16*y+63 = 0

DELTA = (-16)^2-(1*4*63)

DELTA = 4

DELTA > 0

y = (4^(1/2)+16)/(1*2) or y = (16-4^(1/2))/(1*2)

y = 9 or y = 7

(y-7)*(y-9) = 0

((y-7)*(y-9))/3 = 0

((y-7)*(y-9))/3 = 0 // * 3

(y-7)*(y-9) = 0

( y-7 )

y-7 = 0 // + 7

y = 7

( y-9 )

y-9 = 0 // + 9

y = 9

y in { 7, 9 }